outsource from india chennai india programmers freelance php coder freelance outsource scripts programming complicated perl patterns php module installation
outsource from india perl installation and configuration php installation linux system administration US$15,US$19,US$11,US$10 cheap programmer
india outsource outsource india chennai india programmers php perl mysql freelance freelance programmer
SHOWCASE of php and perl scripts CONTACT US for php custom perl scripts
HOME
|  Web expertise  |  Web experience  |  Our Portfolio  |  Our web developers  |  Join us !   |
|  Our Advanced Skills  |  Competitive rates and pricing  |  contact us  |  Software Development  |
 

What References Do

PHP references allow you to make two variables to refer to the same content. Meaning, when you do:

<?php
$a =& $b 
?>

it means that $a and $b point to the same variable.

Note: $a and $b are completely equal here, that's not $a is pointing to $b or vice versa, that's $a and $b pointing to the same place.

The same syntax can be used with functions, that return references, and with new operator (in PHP 4.0.4 and later):

<?php
$bar =& new fooclass();
$foo =& find_var ($bar);
?>

Note: Not using the & operator causes a copy of the object to be made. If you use $this in the class it will operate on the current instance of the class. The assignment without & will copy the instance (i.e. the object) and $this will operate on the copy, which is not always what is desired. Usually you want to have a single instance to work with, due to performance and memory consumption issues.

While you can use the @ operator to mute any errors in the constructor when using it as @new, this does not work when using the &new statement. This is a limitation of the Zend Engine and will therefore result in a parser error.

The second thing references do is to pass variables by-reference. This is done by making a local variable in a function and a variable in the calling scope reference to the same content. Example:

<?php
function foo (&$var)
{
    $var++;
}

$a=5;
foo ($a);
?>

will make $a to be 6. This happens because in the function foo the variable $var refers to the same content as $a. See also more detailed explanations about passing by reference.

The third thing reference can do is return by reference.

Ecommerce shopping carts
Events management projects
Affiliates systems
Large sized web projects
Real estate and vacation rental projects
Asp.net and c# projects
|  Web expertise  |  Web experience  |  Our Portfolio  |  Our web developers  |  Join us !   |
|  Our Advanced Skills  |  Competitive rates and pricing  |  contact us  |  Software Development  |
   Copyright © 1997, 1998, 1999, 2000, 2001, 2002, 2003, 2004, 2005, 2006, 2007 the PHP Documentation Group. Web design and webdevelopment and programming done by Software developers and web programmers
Web Design Copyright © 1999-2007. Chrisranjana Software Solutions Pvt Ltd. syndicate rss feed